User blog comment:Facetheslayer/Richard Harrow (Boardwalk Empire) v. John Marston (Red Dead Redemption)/@comment-5078776-20160111233704

BECAUSE I'M WANTED, WANTED...DEAD OR ALIVE!!! The M1892 takes an edge for me, but it's close. While the Webley's round is slightly larger, the M1892 is a lighter weapon with a longer barrel. Couple those small but key ballistic edges combined with Marston's sharpshooting, and the M1892 takes the edge. Under the assumption of the Model 51 holding an 8-round magazine, it has one more bullet than the M1903. However, I think that the M1903's more combat orientated design- it is a service pistol rather than a pocket pistol- gives it an edge. The 9mm is slightly larger than the .32 ACP, but that difference alone isn't enough. The modern manufacturing marvel takes an edge over the classic pump-action masterpiece. While I personally love pump actions shotguns like the 1897, it simply doesn't compete against the Auto-5 in this case. The gun's semi-auutomatic firing rate simply serves as too much an advantage, especially since it's the only thing different between the two. Personally, I'd've given Marston his more iconic Winchester rifle, but I digress. However, it also wouldn't be able to triumph against the Lee-Enfield rifle. The British rifle is much more accurate, has a further range, can carry more ammunition, and carries a larger round. The Krag-Jorgenson can't compete.
 * Revolver: John Marston
 * Handgun: John Marston
 * Shotgun: Richard Harrow
 * Rifle: Richard Harrow
 * Melee: TBA
 * X-Factors: TBA
 * WINNER: TBA